IP address is an address having information about how to reach a specific host, especially outside the LAN. An IP address is a 32 bit unique address having an address space of 232.
Generally, there are two notations in which IP address is written, dotted decimal notation and hexadecimal notation.
Dotted Decimal Notation
Hexadecimal Notation
Some points to be noted about dotted decimal notation :
1. The value of any segment (byte) is between 0 and 255 (both included).
2. There are no zeroes preceding the value in any segment (054 is wrong, 54 is correct).
Classful Addressing
The 32 bit IP address is divided into five sub-classes. There are two notations for classful addressing, binary notation and decimal notation.
Binary Notation
Example : Find the class of the address 11000001 10000011 00011011 11111111
Solution : The first two bits of the given address are 1, and the third bit is 0. Therefore, it is a class C address.
Decimal Notation
Example : Find the class of the address 227.12.14.87
Solution : The first byte is 227, which is between 224 and 239, and thus, the given address is a class D address.
Net ID and Host ID
Net ID is the part of the IP address that identifies the network; and Host ID is the part of the IP address that identifies the host on the network.
Problems with Classful Addressing:
The problem with this classful addressing method is that millions of class A address are wasted, many of the class B address are wasted, whereas, number of addresses available in class C is so small that it cannot cater the needs of organizations. Class D addresses are used for multicast routing, and are therefore available as a single block only. Class E addresses are reserved.
Because of these problems, Classful networking was replaced by Classless Inter-Domain Routing (CIDR) in 1993. And to discuss it properly let us first understand Network Address, Mask and Subnetting.
Network address - It identifies a network on internet. Using this, we can find range of addresses in the network and total possible number of hosts in the network.
Mask - It is a 32-bit binary number that gives the network address in the address block when AND operation is bitwise applied on the mask and any IP address of the block.
The default mask in different classes are :
Class A – 255.0.0.0
Class B – 255.255.0.0
Class C – 255.255.255.0
Example : Given IP address 132.6.17.85 and default class B mask, find the beginning address (network address).
Solution : The default mask is 255.255.0.0, which means that the only the first 2 bytes are preserved and the other 2 bytes are set to 0. Therefore, the network address is 132.6.0.0.
Subnetting - Dividing a large block of addresses into several contiguous sub-blocks and assigning these sub-blocks to different smaller networks is called subnetting. It is a practice that is widely used when classless addressing is done.
Classless Addressing
To reduce the wastage of IP addresses in a block, we use sub-netting. What we do is that we use host id bits as net id bits of a classful IP address. We give the IP address and define the number of bits for mask along with it (usually followed by a ‘/’ symbol), like, 192.168.1.1/28. Here, subnet mask is found by putting the given number of bits out of 32 as 1, like, in the given address, we need to put 28 out of 32 bits as 1 and the rest as 0, and so, the subnet mask would be 255.255.255.240.
Some values calculated in subnetting :
1. Number of subnets : Given bits for mask – No. of bits in default mask
2. Subnet address : AND result of subnet mask and the given IP address
3. Broadcast address : By putting the host bits as 1 and retaining the network bits as in the IP address
4. Number of hosts per subnet : 2(32 – Given bits for mask) – 2
5. First Host ID : Subnet address + 1 (adding one to the binary representation of the subnet address)
6. Last Host ID : Subnet address + Number of Hosts
Example : Given IP Address – 172.16.0.0/25, find the number of subnets and the number of hosts per subnet. Also, for the first subnet block, find the subnet address, first host ID, last host ID and broadcast address.
Solution : This is a class B address. So, no. of subnets = 2(25-16) = 29 = 512.
No. of hosts per subnet = 2(32-25) – 2 = 27 – 2 = 128 – 2 = 126
For the first subnet block, we have subnet address = 0.0, first host id = 0.1, last host id = 0.126 and broadcast address = 0.127
